Question

∫01∫0(√1−y2)cos(x2+y2)dxdy evaluate the integral by first converting polar coordinates

Answer 1

\[\int\limits_{0}^{1}\int\limits_{0}^{\sqrt(1-y^2)}\cos(x^2+y^2)dxdy\]

Answer 2

\(x = r\cos \theta\)
\(y = r\sin \theta \)

\(dxdy \to rdrd\theta\)

Answer 3

i found the answer (pi/4)*sin(1)

Answer 4

whats your double integral after switching to polar ?

Answer 5

\[\int\limits_{0}^{\pi/2}\int\limits_{0}^{1}\cos(r^2)rdrd\]

Answer 6

Looks good !
http://www.wolframalpha.com/input/?i=%5Cint+%5Climits_0%5E%28pi%2F2%29+%5Cint+%5Climits_0%5E1+r%5Ccos%28r%5E2%29+drd%5Ctheta

Answer 7

i cant open the link :( can you take a photo of it.

Answer 8

http://prntscr.com/3wzc0w

Answer 9

thanks

Answer 10

np :)