Question

∫(2x+y^2(x))dx+(2xy+3y)dy where C is bounded by y=x^2+1, x+y=13 and x=1 with positive orientation

Answer 1

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Answer 2

What ur question?

Answer 3

post it as equation so that it will be easy for others to help u there is an option below the reply space

Answer 4

\[\int\limits_{C}^{}(2x+y^2x)dx+(2xy+3y)dy\]

Answer 5

is it algebra or other if its other then im sorry i dont know

Answer 6

it is calculus 2 :(

Answer 7

i've not studied it yet

Answer 8

thanks anyway

Answer 9

For each section of the curve, you must express x and y (and dx and dy) in terms of a single variable.

For example, along the curve defined by y= x^2 + 1 (and dy = 2x dx)
replace y with x^2+1 and dy with 2x dx in your expression
you will get an expression in terms of x and dx
integrate, using limits of x=1 to 3 (see attached)

Answer 10

\[\int\limits_{?}^{?}\int\limits_{?}^{?}(2x-2xy)dxdy\] i think it is something like this but i need bounds

Answer 11

A line integral along closed curve C can be evaluated using Green's Thm.

if you make the inner integral dy, you would go from the lower curve y=x^2+1 to the upper curve y= 13-x
the outer integral over dx is 1 to 3

Answer 12

\[\int\limits_{1}^{3}\int\limits_{2}^{12}(-2yx+2y)dydx\]

Answer 13

no, the y limits are a function of x
y=x^2+1 to y= 13-x

Answer 14

\[\int\limits_{1}^{3}\int\limits_{x^2+1}^{13-x}(-2yx+2y)dydx\]

Answer 15

yes

Answer 16

thanks