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Mathematics 17 Online
OpenStudy (anonymous):

solve for x 12^x=28

OpenStudy (imstuck):

Is this\[12^{x}=28\]

OpenStudy (anonymous):

yeah but solve for x

OpenStudy (imstuck):

This is a log problem. Are you familiar with logs?

OpenStudy (anonymous):

yeah but they are hard i get confused with logs

OpenStudy (imstuck):

Logs are pretty tedious...I agree. The conversion is this\[x=a ^{y}-->y=\log _{a}(x)\]Does that help you? Look at the way the original is set up and how the variables translate to the log function.

OpenStudy (muzzack):

Solution Steps 1. Simplify Exponents 12=28 There is no solution to this problem.

OpenStudy (imstuck):

What do you get?

OpenStudy (anonymous):

i got 1.340977742749

OpenStudy (imstuck):

Muzzack, you are incorrect. This is a log function.

OpenStudy (anonymous):

im not sure if its right

OpenStudy (imstuck):

This is how to convert between log bases. To get to a base of 10, which is what your calculator is set to find, you do this:

OpenStudy (imstuck):

\[\log _{b}M=\frac{ \log _{a}M }{ \log _{a}b }\]In your case it would be

OpenStudy (imstuck):

\[\log _{12}(28)=\frac{ \log _{10}(28) }{ \log _{10}(12) }\]

OpenStudy (imstuck):

This you can do on your calculator. Do you know how? You now have your logs with bases of 10.

OpenStudy (anonymous):

i think so ill try it out

OpenStudy (imstuck):

Please...and then let me know what you get. AND write that conversion down...you may need it again!

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

yeah i was right its approx 1.340977742749 how can i make it shorter is it 1.3409?

OpenStudy (imstuck):

That's good! Good job!

OpenStudy (anonymous):

thank you

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