Question

Hello, i need some help and i guess this website can help? i was just wondering if there's a trick to solving inequalities faster than the standard method? Thanks.

Answer 1

Hello captain welcome to OpenStudy there are a lot of friendly people here who can help you :3

Answer 2

That's good, im doing credit recovery for my freshman year with plato, and normally im good with math, but this stumps me.

Answer 3

well what is your question?

Answer 4

faster? not really. ou have an example?

Answer 5

well..inequalities are solved pretty much like equations. I don't know if there is a short cut

Answer 6

I'm doing the same thing captain

Answer 7

inequalites are solved 'just like' equations .... we can apply the same rules to both cases

Answer 8

except for the rule about the multiplying/dividing by a negative

Answer 9

no, that rule works for both cases

Answer 10

-3x = 9 ... divide both sides by -3 and flip the equation sign ....

Answer 11

how ? your not gonna change the equal sign ?

Answer 12

\[-\frac{ 1 }{ 4}x+2>4\] I have serious problems with the fractions and following the rule. I get the multiplying and dividing mixed up constantly.

Answer 13

why not change it?

Answer 14

to get rid of the denominator, mutliply thru the setup by the denominator

Answer 15

so multiply the last 4 by 4 and that gets rid of the fraction?

Answer 16

multiply it ALL by 4 for get rid of the fraction

Answer 17

(4) 1/4x + 2(4) > 4(4)

Answer 18

but couldn't I get rid of the 2 first by subtracting it from itself and the latter 4 to make it even more simple before I multiply?

Answer 19

oops.... (4) - 1/4

Answer 20

yes..you can subtract 2 first if you want to

Answer 21

make it more simple? thats not a mathical thing. thats a psychological thing

Answer 22

but yes, you can if you want :)

Answer 23

Oh alright

Answer 24

So my answer is [x=-8] then because a positive times a negative is a negative right?

Answer 25

your answer is a set of values that satisfy the setup ... there is hopefully more than just one in this case

Answer 26

so I should plug it in the check my answer correct?

Answer 27

-8 is more like a boundary ... when x=-8 the setup is EQUAL to 4 ... we want to know when it is LESS than 4

Answer 28

-1/4x + 2 > 4
-1/4x > 2 -- multiply both sides by 4
-x > 8
x < 8

Answer 29

err, GREATER than 4 .. bad memory

Answer 30

oops...x < -8

Answer 31

and so x<-8 Is the solution set, and then.. plato is telling me now to make the x a -12 but I don't understand how that happened

Answer 32

is -12 less than -8?

Answer 33

yas
ooOOHH

Answer 34

*mind goes capew*

Answer 35

soo .... if all x less than -8 are solutions, test one of them out. lol

Answer 36

right so it doesn't matter whats plugged In as long as its less than -8?

Answer 37

the -12 is used just to check the answer...you could have used any number that is less the -8....

Answer 38

correct

Answer 39

we could have used x=0 to see if x > -8 is false as well

Answer 40

AHhhh okay. I understand. Plato had me confuzzled.

Answer 41

lol......silly Plato

Answer 42

Thanks guys. Big help ^.^

Answer 43

thats what we are here for :)

Answer 44

we know x=-8 is equal to 4, so it has to seperate a true side from a false side

<-----------( )------------->
-8

since 0 is usually the simplest check; does x=0 make a true or false statement?

-1/4 (0) + 2 > 4
2 > 4 is false, so the side with x=0 has to be false


true false
<-----------( )-----------|-->
-8 0

Answer 45

that makes so much more sense. I saw the number line on the plato page but I completely overlooked it.

Answer 46

:) good luck