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Mathematics 16 Online
OpenStudy (anonymous):

I need help ASAP please.

OpenStudy (anonymous):

with these two questions

OpenStudy (anonymous):

medal is given

OpenStudy (anonymous):

i need to get this test done by today or i fail please help me!!!

OpenStudy (anonymous):

\[\sqrt{7}/\sqrt[4]{7}= 7^{1/2}/7^{1/4}\]

OpenStudy (anonymous):

you do the same thing

OpenStudy (anonymous):

i say it is answer a

OpenStudy (anonymous):

first one you have correct

OpenStudy (anonymous):

let me see...

OpenStudy (anonymous):

did you get the answer?

OpenStudy (anonymous):

i keep getting 8 3/10 but it is not negative

OpenStudy (anonymous):

its whatever your heart tells you

OpenStudy (imstuck):

The second one is the third choice from the top.

OpenStudy (imstuck):

\[\frac{ \sqrt[5]{8}\sqrt{8} }{ \sqrt[3]{8^{5}} }\]That equals, in exponential form:

OpenStudy (imstuck):

\[\frac{ 8^{\frac{ 1 }{ 5 }}8^{\frac{ 1 }{ 2 }} }{ (8^{5})^{\frac{ 1 }{ 3 }} }\]

OpenStudy (imstuck):

In the numerator you have to find a common denominator and add those exponents, and in the denominator you multiply the 5 times the one-third to get 8^5/3.

OpenStudy (imstuck):

The numerator becomes \[8^{\frac{ 7 }{ 10 }}\]and the denominator is\[8^{\frac{ 5 }{ 3 }}\]Because these are divided, you are required to subtract the exponent in the denominator from the exponent in the numerator.

OpenStudy (imstuck):

\[8^{(\frac{ 7 }{ 10 }-\frac{ 5 }{ 3 })}\]Now you have to find a common denominator between the 10 and the 3 which is 30.

OpenStudy (imstuck):

\[8^{(\frac{ 21 }{ 30 }-\frac{ 50 }{ 30 })}\]

OpenStudy (imstuck):

This gives you \[8^{-\frac{ 29 }{ 30 }}\]

OpenStudy (anonymous):

^ correct i see where i went wrong

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