A 39 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1024. N = N0e -kt N0 = initial mass (at time t = 0) N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days Find the substance's half-life, in days. Round your answer to the nearest tenth.
@Pizza7
@iambatman
ok we get the picture now? go straight to the answer. it is −ln(.5)÷0.1374 use a caclulator natural log of one half divided by the natural log of k, get rid of the minus sign to the tenth it is 50.4 but you should check in case i give you the wrong answer
I dont Know
google gave me 5.04473930539
the formula for half-life is \(t_{1/2}=\dfrac{ln(2)}{k}\)
ok
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