Lines CD and DE are tangent to circle A as shown below:
If arc CE is 110°, what is the measure of ∠CDE?
55°
70°
100°
125°
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OpenStudy (anonymous):
OpenStudy (anonymous):
@agent0smith
OpenStudy (anonymous):
@agent0smith
OpenStudy (anonymous):
@amistre64
OpenStudy (anonymous):
@Compassionate
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OpenStudy (anonymous):
@JuanitaM
OpenStudy (anonymous):
Since the arc is 110 degrees - the bigger arc is 250
so to find the <CDE take 1/2 of bigger arc
OpenStudy (anonymous):
how would i do that? @JuanitaM
OpenStudy (anonymous):
if the bigger arc is 250 - what is 1/2 of that?
OpenStudy (anonymous):
125
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
oh okayy thank you so much i get it now! lol
OpenStudy (anonymous):
you are welcome
OpenStudy (amistre64):
i dont get 125
OpenStudy (amistre64):
there are a few ways to appraoch it; one is an average of arcs, the other is by making a kite.
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the angles of the kite have to add up to 360
x + 180 + 110 = 360 is one route
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the average of angles is essentially:\[\frac{(360-110)-110}{2}=\frac{180-110}{2}\]
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OpenStudy (amistre64):
lol, that last /2 was a brainurism
OpenStudy (amistre64):
180-110 ... which is not going to be 125
OpenStudy (anonymous):
70?
OpenStudy (amistre64):
i see juanita was thinking of a different property that corresponds to angles inside of a circle
OpenStudy (amistre64):
70 is the correct answer yes
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OpenStudy (anonymous):
oh okayy thanks
OpenStudy (amistre64):
this is correct for a differnt problem, not this one :)
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