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Mathematics 13 Online
OpenStudy (anonymous):

What is the simplified form of the expression the square root of the quantity 16 times c to the eighth power. - the square root of c squared. + 5 the square root of c squared. + the square root of the quantity 4 times c squared.? 8c4 + 8c 4c4 + 8c 8c4 + 6c 4c4 + 6c

OpenStudy (anonymous):

Hey, I think I can help with this. Let me work through it and make sure I've got the right idea. :)

OpenStudy (anonymous):

This is the expression btw if it helps

OpenStudy (anonymous):

So sorry. Helping a few other people. I'm back.

OpenStudy (anonymous):

Ok :)

OpenStudy (anonymous):

That does help, thanks!

OpenStudy (anonymous):

Do you have any answer choices?

OpenStudy (anonymous):

8c4 + 8c 4c4 + 8c 8c4 + 6c 4c4 + 6

OpenStudy (anonymous):

Hello, idiot...so sorry

OpenStudy (anonymous):

ok i think i have an easier question you can help me with if you're willing

OpenStudy (anonymous):

Def., I'll figure this one out, too, tho

OpenStudy (anonymous):

Sorry, it's just I'm not an expert and this is something I learned a few months ago so I'm digging into the depths of my brain to remember

OpenStudy (anonymous):

But I WILL get it, LOL

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

if you figure out 1 of the two I will be so grateful because I have no idea what this stuff is tbh

OpenStudy (anonymous):

Simplifying radicals. Sorry, had to finish up with the other person. K, let me take a look at this second one.

OpenStudy (anonymous):

Are you in FLVS? :)

OpenStudy (anonymous):

Found it in my notebook. Now I can teach you how to do it. Momentito.

OpenStudy (anonymous):

I don't need help with the 2nd one anymore just the first please. The first one is my last question.

OpenStudy (anonymous):

are you still there?

OpenStudy (anonymous):

Yes! It is D. Let me walk you through it.

OpenStudy (anonymous):

So sorry that took so long. You don't have to give me a medal. Alright, so here's how you do it: The first term is 16 sqrt c^8. 16 is a perfect square - when you take its square root, you get 4, right? So that gives you 4 sqrt c^8. How many times does c^2 go into c^8?

OpenStudy (anonymous):

4. So that simplifies the first term (which was the most complicated) to 4c^4. The second term is simplified, and so is the third. The fourth term has a coefficient of 4 within the radical, and if you take its square root, you just write a 2 outside of sqrt c^2.

OpenStudy (anonymous):

You deserve it thank you for taking your time to help me. Unfortunately i'm in rush to be somewhere so I have to go. But again, Thank you so much!

OpenStudy (anonymous):

Now it's simple addition and subtraction. 4c^4 - sqrt c^2 + 5 sqrt c^2 + 2 sqrt c^2. You can make all the sqrt c^2 terms into just c. That's -1 + 5 + 2 = 6. 4c^4 + 6c. Good luck!

OpenStudy (anonymous):

Btw it was right

OpenStudy (anonymous):

Aw, thanks. Sorry it took so long. I'm just getting into helping other students on here.

OpenStudy (anonymous):

Did you get the 2nd one right?

OpenStudy (anonymous):

and yes i did get the 2nd one it was\[42k \sqrt{5k}\]

OpenStudy (anonymous):

Awesome job! Let me know if you need any more help (any time).

OpenStudy (anonymous):

Go ahead and close this question :)

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