Question

What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56?

Answer 1

all you need to common difference. the easy way is

\[d =\frac{ (56 - 8)}{(9 - 1) }\]



when you get that you'll need to formula for a term in an arithmetic sequence

\[a_{N} = a_{1} + ( n - 1) \times d\]

you know n = 24 and you know a1 = 8

hope it helps

Answer 2

d = 6 an= 8 + (24-1) x 6

Answer 3

thst looks good to mr

Answer 4

an = 8 + 23 x 6 = 8 + 138 = 146?

Answer 5

Thank you very much