Question

Find the slope of the line passing through each pair or points or state that the slope is undefined. Then indicate whether the line through the points rises, falls, is horizontal, or is vertical.

(4, -2) and (3, -2)

I'm confused.
With \[\frac{ y ^{2}-y^{1} }{ x ^{2} - x ^{1} }\]

I got \[\frac{ 0 }{ -1 }\]

and with

(4, -2)
(3, -2)

I got +1 from 4 and 3 and then I got 0 from -2 and - 2 which resulted in \[\frac{0 }{ 1 }\]

Where am I messing up at? I think they're both incorrect...

Answer 1

nope, they;re correct

Answer 2

How come one came out negative and the other came out positive?

Answer 3

well.. the second... which is the 1st I guess, is also 0/-1

Answer 4

oooh...is that even a slope? or is that undefined? I think it would only go horizontally to the left if that's the case

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ -2}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ -2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -2}}-{\color{blue}{ (-2)}}}{{\color{red}{ 3}}-{\color{red}{ 4}}}\implies \cfrac{-2+2}{3-4}\implies \cfrac{0}{-1}\to 0\)

Answer 6

yes

Answer 7

well...

Answer 8

how do you know the y-intercept's -2 o.o

Answer 9

is a "linear equation", thus it makes a line, I just plotted the 2 given points

so there's only 1 possible intercept for a line with those points

Answer 10

I see, thank you very much. c:

Answer 11

yw