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Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.
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you tried ? you know the formula. plug in alues
*values
2nd term = -21 n=2, a2 = -21
Oh I just noticed it is geometric
yep, so formula is \(\Large a_n = a_1 r^{n-1}\)
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to find r do I just divide 567 by -21 ?
plug in those values a2 = -21 n= 2 you will get one equation in a1 and r
then plug in a5 = 567 n=5 you will get another equation in a1 and r
\[a _{n} = 6 * -27^{n-1}\]
\(-21= a_1 r\) \(567 =a_1 r^4\)
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divide those
you will get r^3
divide what
|dw:1403914079164:dw|
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