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Mathematics 10 Online
OpenStudy (fanduekisses):

Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.

hartnn (hartnn):

you tried ? you know the formula. plug in alues

hartnn (hartnn):

*values

hartnn (hartnn):

2nd term = -21 n=2, a2 = -21

OpenStudy (fanduekisses):

Oh I just noticed it is geometric

hartnn (hartnn):

yep, so formula is \(\Large a_n = a_1 r^{n-1}\)

OpenStudy (fanduekisses):

to find r do I just divide 567 by -21 ?

hartnn (hartnn):

plug in those values a2 = -21 n= 2 you will get one equation in a1 and r

hartnn (hartnn):

then plug in a5 = 567 n=5 you will get another equation in a1 and r

OpenStudy (fanduekisses):

\[a _{n} = 6 * -27^{n-1}\]

hartnn (hartnn):

\(-21= a_1 r\) \(567 =a_1 r^4\)

hartnn (hartnn):

divide those

hartnn (hartnn):

you will get r^3

OpenStudy (fanduekisses):

divide what

hartnn (hartnn):

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