Question

Ayudar?

Answer 1

\(\bbox[1pt,#FF0000]{\bbox[1pt,#FF1700]{\bbox[1pt,#FF2E00]{\bbox[1pt,#FF4500]{\bbox[1pt,#FF5C00]{\bbox[1pt,#FF7300]{\bbox[1pt,#FF8A00]{\bbox[1pt,#FFA100]{\bbox[1pt,#FFB800]{\bbox[1pt,#FFCF00]{\bbox[1pt,#FFE600]{\bbox[1pt,#FFFD00]{\bbox[1pt,#FFff00]{\bbox[1pt,#E8ff00]{\bbox[1pt,#D1ff00]{\bbox[1pt,#BAff00]{\bbox[1pt,#A3ff00]{\bbox[1pt,#8Cff00]{\bbox[1pt,#75ff00]{\bbox[1pt,#5Eff00]{\bbox[1pt,#47ff00]{\bbox[1pt,#30ff00]{\bbox[1pt,#19ff00]{\bbox[1pt,#02ff00]{\bbox[1pt,#00ff00]{\bbox[1pt,#00ff17]{\bbox[1pt,#00ff2E]{\bbox[1pt,#00ff45]{\bbox[1pt,#00ff5C]{\bbox[1pt,#00ff73]{\bbox[1pt,#00ff8A]{\bbox[1pt,#00ffA1]{\bbox[1pt,#00ffB8]{\bbox[1pt,#00ffCF]{\bbox[1pt,#00ffE6]{\bbox[1pt,#00ffFD]{\bbox[1pt,#00ffff]{\bbox[1pt,#00FDff]{\bbox[1pt,#00E6ff]{\bbox[1pt,#00CFff]{\bbox[1pt,#00B8ff]{\bbox[1pt,#00A1ff]{\bbox[1pt,#008Aff]{\bbox[1pt,#0073ff]{\bbox[1pt,#005Cff]{\bbox[1pt,#0045ff]{\bbox[1pt,#002Eff]{\bbox[1pt,#0017ff]{\bbox[1pt,#0000ff]{\bbox[1pt,#0200ff]{\bbox[1pt,#1900ff]{\bbox[1pt,#3000ff]{\bbox[1pt,#4700ff]{\bbox[1pt,#5E00ff]{\bbox[1pt,#7500ff]{\bbox[1pt,#8C00ff]{\bbox[1pt,#A300ff]{\bbox[1pt,#BA00ff]{\bbox[1pt,#D100ff]{\bbox[1pt,#E800ff]{\bbox[1pt,#FF00ff]{\bbox[1pt,#FF00FD]{\bbox[1pt,#FF00E6]{\bbox[1pt,#FF00CF]{\bbox[1pt,#FF00B8]{\bbox[1pt,#FF00A1]{\Huge\mathbb{\color{white}{Help?\ :D}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}\)

Answer 2

The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price of two products, A and B, over time.

The price f(x), in dollars, of product A after x years is represented by the function below.

f(x) = 10250(0.63)x

Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. (5 points)

Part B: The table below shows the price f(t), in dollars, of product B after t years:


t (number of years) 1 2 3 4
f(t) (price in dollars) 4300 1849 795.07 341.88


Which product recorded a greater percentage change in price over the previous year? Justify your answer. (5 points)

Answer 3

\(\Huge\color{cyan}{I~Already~Have~Part~A~Done.}\)

Answer 4

@ParthKohli help plz?

Answer 5

Do you know the formula for this ? :)

Answer 6

no...

Answer 7

\[\frac{ (old - new) }{ old }\]

Answer 8

whats old and new?

Answer 9

old would be the price 1 and new would be price 2

Answer 10

\[\frac{ (4300-1849) }{ 4300 }\] Thats our first equation

Answer 11

4300 * k =1849
k=1849/4300 = 0.43
there fore 1-0.43 = 0.57 = 57% drop

Answer 12

k is telling us what percentage of 4300 we have to get 1849.
if we have k percentage left that means we lost 100%-k%

Answer 13

The answer of the first equation i gave you is .57 . So the percent increase between price 1 and 2 is 57%

Answer 14

Therefore part B recording greater drops as it is 57% and...
Since Part A is only recording 1-0.63=0.37, 37% drop

Answer 15

Sorry not percent increase the change in percent

Answer 16

whoa whoa whoa a bit too fast

Answer 17

so whats the percent increase for part A to B?

Answer 18

Now we find the percent difference between price 2 and 3

Answer 19

\[\frac{ (1849-795.07) }{ 1849}\]

Answer 20

There is also a 57 percent difference between price 2 and 3

Answer 21

so its more than price 1 to 2?

Answer 22

Now the last one the price difference between price 3 and 4

Answer 23

Well actually its the same the 1-2 ans 2-3 are both 57%

Answer 24

oh ok so its probably 3 to 4 with the greatest right?

Answer 25

\[\frac{ (795.07-341.88) }{ 795.07 }\]

Answer 26

Yeah The difference is 92%

Answer 27

wow o_o

Answer 28

Thank You!

Answer 29

No problem ! You even have the work to prove your answer ! :)