Question

tanx+tany=a, cotx+coty=b
Pt cot(x+y) =1/a +1/b?

Answer 1

use the cot(A+B) formula :
\(\Large \cot(A+B) = \dfrac{\cot A \cot B -1}{\cot A+\cot B}\)

Answer 2

you already have the denominator

use tan x + tan y = a
convert tan to cot

Answer 3

Will try and ping...

Answer 4

although you will get cot(x+y) =1/a -1/b
so please verify your question....

Answer 5

{(1/tanx*1/tany) - 1} /b
How to solve?

Answer 6

tanx+tany=a

1/cot x+1/cot y = a

(cot y +cot x)/ (cot y cot x) = a

b/ (cot y cot x) = a

got this ?

Answer 7

Ya...

Answer 8

Cotycotx is (1/tanx) (1/tany) right?

Answer 9

yes

but lets keep it as cot y cot x


b/ (cot y cot x) = a

cot y cot x = b/a
right ?

Answer 10

now you have numerator too

Answer 11

Thanks a lot! :) :)

Answer 12

welcome ^_^