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Mathematics 10 Online
OpenStudy (unklerhaukus):

What is the difference between +∞ and ∞ ?

OpenStudy (anonymous):

I don't know that there is one.

OpenStudy (anonymous):

0

OpenStudy (anonymous):

"+" if we are comparing and contrasting.

OpenStudy (anonymous):

I thought \(\infty\) is \(+\infty\), just as \(7\) is \(+7\).

OpenStudy (anonymous):

\[+\infty-\infty= ?\]

OpenStudy (anonymous):

I think of it as: \[ +\infty \equiv 0+\infty = \infty \]

OpenStudy (anonymous):

Just as \[ -\infty \equiv 0-\infty \]

OpenStudy (unklerhaukus):

no

hartnn (hartnn):

infinity is a concept, not a number that can be subtracted... or did you ask the difference in concepts :P

OpenStudy (anonymous):

@hartnn I disagree.

OpenStudy (dumbsearch2):

+∞ means above 0? I don't know...

OpenStudy (anonymous):

@UnkleRhaukus What are you talking about?

hartnn (hartnn):

infinity is a number ?

OpenStudy (anonymous):

It's both

OpenStudy (anonymous):

It is not technically a number, but that doesn't mean much. The 'number' is slightly arbitrary classification anyway, just like how prime numbers exclude.

OpenStudy (anonymous):

The only point of 'infinity is not a number' is to basically to exclude infinity from most of our algebraic properties and such.

OpenStudy (anonymous):

It's actually just a concept, maybe because we can't comprehend it. But then again googolplex is also a number but we can't really comprehend that either.

OpenStudy (anonymous):

infinity breaks a lot of algebra, so we exclude it to avoid having to put an asterisk next to everything.

OpenStudy (anonymous):

Maybe the plus sign gives infinity direction or value

OpenStudy (anonymous):

Saying "infinity is not a number" is like saying "\(i\) is not a real number". The only point is that it doesn't apply in formulas that apply only to numbers. Same way certain formulas about real numbers don't apply to complex numbers.

OpenStudy (anonymous):

+∞ is above the x axis..... And - ∞ is below the x axis.....

OpenStudy (anonymous):

\[\infty = scalar~~~ + \infty = vector ? \]

OpenStudy (anonymous):

We can add, subtract, and multiply infinity as if it were a number, it's just that it often leads to an indeterminant form. \(0-\infty \) and \(0+\infty\) are prefectly valid.

OpenStudy (anonymous):

Wait... did you mean difference as in ... \(+\infty - \infty\)? I thought you meant the difference as in like, are they fundamentally different concepts...

OpenStudy (unklerhaukus):

My professor was insisting that +∞ is more precise than ∞, and that ∞ was abuse of notation; I really didn't understand

OpenStudy (anonymous):

But \(+7\) isn't an abuse of notation? I'm not sure I agree with him.

OpenStudy (anonymous):

whoops, I mean \(7\) instead of \(+7\).

OpenStudy (anonymous):

Always increasing to an undetermined numerical value?

OpenStudy (anonymous):

Well when using limits it doesn't really effect it?

OpenStudy (anonymous):

Unless you view left and right side limits

OpenStudy (anonymous):

Or piecewise functions

OpenStudy (anonymous):

I think your prof is just being picky, Unkle.

OpenStudy (anonymous):

Either notation is fine \[\lim_{x \rightarrow \infty} ~~~ or ~~~ \lim_{x \rightarrow + \infty}\] unless you look at both + and - and see if it exists or not, other wise I don't see what the big deal is?

OpenStudy (anonymous):

Unless \(\infty\) without a \(+\) somehow adds ambiguity... but I don't see how it would?

OpenStudy (anonymous):

Abuse of notation!

OpenStudy (accessdenied):

I vaguely remember some set of numbers that included one infinity that stood for both positive and negative infinity, because it wrapped around on itself. I doubt that's the real reason for distinguishing the two and there probably isn't really one, but just a thought I had. lol

OpenStudy (anonymous):

There are various types of complex infinities.

OpenStudy (anonymous):

Like \[ \lim_{n\to \infty} an+bni \]

OpenStudy (unklerhaukus):

go on, , ,

OpenStudy (anonymous):

What else is there to say? Basically you have \[ \theta = \arctan\left(\frac ba\right) \]Since \(\theta \in [0,2\pi)\), the set of complex infinities is an infinite, uncountable set.

OpenStudy (anonymous):

For \(\theta = 0\), you have \(+\infty\). For \(\theta = \pi\), you have \(-\infty\). You can multiply these infinity and get \((+\infty)(-\infty) = -\infty\). You can probably do something similar with complex infinity.

OpenStudy (anonymous):

If you do \[ \lim_{n\to \infty}n + i \]Then it would seem to go to \(\infty + i\). What would happen then? The angle would appear to be \(0\).

OpenStudy (anonymous):

So does \(\infty+i = \infty\) then?

OpenStudy (unklerhaukus):

hmmm

OpenStudy (anonymous):

Well, it's not too far fetched. \(\infty + 1 = \infty\).

OpenStudy (anonymous):

One thing to keep in mind about all of this... and that is that \(\infty \) is shorthand for \(\lim_{n\to \infty} n\) when it is used outside of a limit.

OpenStudy (anonymous):

So what I really mean by \(\infty + 1 = \infty\) is \[ \lim_{n\to \infty}n+1 = \lim_{n\to\infty}n \]

OpenStudy (unklerhaukus):

isn't that a recursive definition?

OpenStudy (anonymous):

No, I said "when it is outside of a limit".

OpenStudy (anonymous):

Both \[ \lim_{x\to \infty}f(x) = L \]and \[ \lim_{x\to a}f(x) = \infty \]and all the other combinations have their own definitions. And those definitions do not include infinity.

OpenStudy (unklerhaukus):

Then what does ∞ mean when it is inside the limit

OpenStudy (anonymous):

Outside of the context of limts, I don't think \(\infty\) has a meaning as far as I know.

OpenStudy (anonymous):

\[ \lim_{x\to \infty}f(x) = L \]This means \[\forall \epsilon \exists \delta \forall x\quad x>N\implies |f(x)-L|<\epsilon \]

OpenStudy (anonymous):

Whoops, change \(\exists \delta\) to \(\exists N\).

OpenStudy (anonymous):

Or just put \(\delta\) in there.

OpenStudy (anonymous):

\[ \lim_{x\to -\infty}f(x) = L \]This means \[\forall \epsilon \exists \delta \forall x\quad x<\delta \implies |f(x)-L|<\epsilon \]

OpenStudy (anonymous):

\[ \lim_{x\to a}f(x) = \infty \]This means \[\forall \epsilon \exists \delta \forall x\quad |x-a|<\delta \implies f(x)>\epsilon \] \[ \lim_{x\to a}f(x) =- \infty \]This means \[\forall \epsilon \exists \delta \forall x\quad |x-a|<\delta \implies f(x)<\epsilon \]

OpenStudy (anonymous):

Notice how the definitions for limits where you have \(x\to \pm \infty\), they resemble one-sided limits. Technically they are one-sided limits since \(\infty\) is like a wall and you can't approach from the other side.

OpenStudy (anonymous):

In my opinion, these definitions of limits also define infinity, and infinity doesn't have any formal meaning outside of them.

OpenStudy (anonymous):

Even \[ \int\limits_{-\infty}^{\infty} \]is just \[ \lim_{t\to-\infty}\lim_{s\to \infty} \int\limits_t^s \]

OpenStudy (anonymous):

Limits are unwieldy and don't always play by the rules of algebra, thus infinity is unwieldy as well.

OpenStudy (ikram002p):

this is a diffrence :D |dw:1403940999593:dw|

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