What is the difference between +∞ and ∞ ?
I don't know that there is one.
0
"+" if we are comparing and contrasting.
I thought \(\infty\) is \(+\infty\), just as \(7\) is \(+7\).
\[+\infty-\infty= ?\]
I think of it as: \[ +\infty \equiv 0+\infty = \infty \]
Just as \[ -\infty \equiv 0-\infty \]
no
infinity is a concept, not a number that can be subtracted... or did you ask the difference in concepts :P
@hartnn I disagree.
+∞ means above 0? I don't know...
@UnkleRhaukus What are you talking about?
infinity is a number ?
It's both
It is not technically a number, but that doesn't mean much. The 'number' is slightly arbitrary classification anyway, just like how prime numbers exclude.
The only point of 'infinity is not a number' is to basically to exclude infinity from most of our algebraic properties and such.
It's actually just a concept, maybe because we can't comprehend it. But then again googolplex is also a number but we can't really comprehend that either.
infinity breaks a lot of algebra, so we exclude it to avoid having to put an asterisk next to everything.
Maybe the plus sign gives infinity direction or value
Saying "infinity is not a number" is like saying "\(i\) is not a real number". The only point is that it doesn't apply in formulas that apply only to numbers. Same way certain formulas about real numbers don't apply to complex numbers.
+∞ is above the x axis..... And - ∞ is below the x axis.....
\[\infty = scalar~~~ + \infty = vector ? \]
We can add, subtract, and multiply infinity as if it were a number, it's just that it often leads to an indeterminant form. \(0-\infty \) and \(0+\infty\) are prefectly valid.
Wait... did you mean difference as in ... \(+\infty - \infty\)? I thought you meant the difference as in like, are they fundamentally different concepts...
My professor was insisting that +∞ is more precise than ∞, and that ∞ was abuse of notation; I really didn't understand
But \(+7\) isn't an abuse of notation? I'm not sure I agree with him.
whoops, I mean \(7\) instead of \(+7\).
Always increasing to an undetermined numerical value?
Well when using limits it doesn't really effect it?
Unless you view left and right side limits
Or piecewise functions
I think your prof is just being picky, Unkle.
Either notation is fine \[\lim_{x \rightarrow \infty} ~~~ or ~~~ \lim_{x \rightarrow + \infty}\] unless you look at both + and - and see if it exists or not, other wise I don't see what the big deal is?
Unless \(\infty\) without a \(+\) somehow adds ambiguity... but I don't see how it would?
Abuse of notation!
I vaguely remember some set of numbers that included one infinity that stood for both positive and negative infinity, because it wrapped around on itself. I doubt that's the real reason for distinguishing the two and there probably isn't really one, but just a thought I had. lol
There are various types of complex infinities.
Like \[ \lim_{n\to \infty} an+bni \]
go on, , ,
What else is there to say? Basically you have \[ \theta = \arctan\left(\frac ba\right) \]Since \(\theta \in [0,2\pi)\), the set of complex infinities is an infinite, uncountable set.
For \(\theta = 0\), you have \(+\infty\). For \(\theta = \pi\), you have \(-\infty\). You can multiply these infinity and get \((+\infty)(-\infty) = -\infty\). You can probably do something similar with complex infinity.
If you do \[ \lim_{n\to \infty}n + i \]Then it would seem to go to \(\infty + i\). What would happen then? The angle would appear to be \(0\).
So does \(\infty+i = \infty\) then?
hmmm
Well, it's not too far fetched. \(\infty + 1 = \infty\).
One thing to keep in mind about all of this... and that is that \(\infty \) is shorthand for \(\lim_{n\to \infty} n\) when it is used outside of a limit.
So what I really mean by \(\infty + 1 = \infty\) is \[ \lim_{n\to \infty}n+1 = \lim_{n\to\infty}n \]
isn't that a recursive definition?
No, I said "when it is outside of a limit".
Both \[ \lim_{x\to \infty}f(x) = L \]and \[ \lim_{x\to a}f(x) = \infty \]and all the other combinations have their own definitions. And those definitions do not include infinity.
Then what does ∞ mean when it is inside the limit
Outside of the context of limts, I don't think \(\infty\) has a meaning as far as I know.
\[ \lim_{x\to \infty}f(x) = L \]This means \[\forall \epsilon \exists \delta \forall x\quad x>N\implies |f(x)-L|<\epsilon \]
Whoops, change \(\exists \delta\) to \(\exists N\).
Or just put \(\delta\) in there.
\[ \lim_{x\to -\infty}f(x) = L \]This means \[\forall \epsilon \exists \delta \forall x\quad x<\delta \implies |f(x)-L|<\epsilon \]
\[ \lim_{x\to a}f(x) = \infty \]This means \[\forall \epsilon \exists \delta \forall x\quad |x-a|<\delta \implies f(x)>\epsilon \] \[ \lim_{x\to a}f(x) =- \infty \]This means \[\forall \epsilon \exists \delta \forall x\quad |x-a|<\delta \implies f(x)<\epsilon \]
Notice how the definitions for limits where you have \(x\to \pm \infty\), they resemble one-sided limits. Technically they are one-sided limits since \(\infty\) is like a wall and you can't approach from the other side.
In my opinion, these definitions of limits also define infinity, and infinity doesn't have any formal meaning outside of them.
Even \[ \int\limits_{-\infty}^{\infty} \]is just \[ \lim_{t\to-\infty}\lim_{s\to \infty} \int\limits_t^s \]
Limits are unwieldy and don't always play by the rules of algebra, thus infinity is unwieldy as well.
this is a diffrence :D |dw:1403940999593:dw|
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