Question

Find the sum upto n terms 1+1+2/2 + 1+2+3/3 1+2+3+4/4 +.........

Answer 1

\[1+ (1+2/2) + (1+2+3/3) +( 1+2+3+4/4)\]

Answer 2

@dan815 pls help

Answer 3

@ShadowLegendX @wio @ParthKohli pls help

Answer 4

pls help

Answer 5

i see sum (a + n)/n lowest 0 highest n
but this is not complete need to account for the repeat

Answer 6

i have redused denominator to n(n+1)/2

Answer 7

a + (a + n)/n + ...

Answer 8

but i am thinking that i should take the no of terms as AP
So i redused the numerator as n'(n'+1)/2

Answer 9

@triciaal any ideas

Answer 10

@ParthKohli pls help

Answer 11

sum of (n + 1)/n + 1

sorry i can't do more i have to go

Answer 12

ok

Answer 13

@ParthKohli sir any ideas

Answer 14

\[\sum \dfrac{1 + 2 + 3\cdots n}{n}\]\[= \sum \dfrac{n(n+1)/2}{n} \]\[= \sum \dfrac{n+1}{2}\]\[= \dfrac{1}{2}\sum(n+1)\]

Answer 15

thank u sir

Answer 16

:)
You have to do one more step of work though. Find \(\sum (n+1)\). It should be very easy.

Answer 17

yes sir

Answer 18

Don't call me "sir" :P

Answer 19

ok

Answer 20

thank u once again

Answer 21

No problem :)