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I just need someone to check this Solve the triangle. A = 52°, b = 10, c = 7
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for a i got 12
for C i got 43.9
and for B i got 84.1
@iPwnBunnies
surely appreciate your having done this much work before asking for help. Congrats. Let's try applying the Law of Cosines to find the length of side a. The Law states:\[a^2=b^2+c^2-2bc*\cos A\]
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Mind calculating ' -2bc*cos A '? Show your work. The reason I ask you to do this is that I get a different result for the length of side a.
7.9!! thats what i got first for a
-( b )( c )cos ( A ) = -(10)(7)cos (52 deg) = -70*cos (52 deg) = ??
Once you have that value, add 10^2 and 7^2 to it. Your result?
7.9
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