The quadratic equation whose root are in A.M and H.M is equal to the sum of squares of their reciprocals, 2x^2-3x+5=0 is
(A) 4x^2-3x+5=0
(B)12x^2-49x+30=0
(C)14x^2-12x+35=0
(D)2x^2+3x+5= 0
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OpenStudy (kanwal32):
@dan815 pls help
OpenStudy (kanwal32):
@luigi0210 pls save my life
OpenStudy (kanwal32):
@hartnn pls help
hartnn (hartnn):
i am not clear with the question...whose roots are in AM?
OpenStudy (kanwal32):
i will rewrite the question
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OpenStudy (kanwal32):
The quadratic equation whose roots are the AM and HM between the roots of the equation 2x^2-3x+5=0
OpenStudy (kanwal32):
is- and option are the same
hartnn (hartnn):
better.
OpenStudy (kanwal32):
i am sorry
OpenStudy (kanwal32):
a bit tensed
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hartnn (hartnn):
no problem. :)
so,
2x^2-3x+5=0
can you find sum of roots and product of roots of this quadratic ?
OpenStudy (kanwal32):
yes
hartnn (hartnn):
AM means arithmetic mean.
AM of 2 numbers will be sum of those 2 numbers divided by 2
so what will be the AM ?
OpenStudy (kanwal32):
wait for a minute
OpenStudy (kanwal32):
but there are no real roots for this equation
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hartnn (hartnn):
you can still find the sum of roots.
have you ever head that
sum if roots for \(ax^2+bx+c\) would be \(\Large \dfrac{-b}{a}\)
?
OpenStudy (kanwal32):
no
OpenStudy (kanwal32):
ok
OpenStudy (kanwal32):
so 3/2
hartnn (hartnn):
correct.
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hartnn (hartnn):
now product of roots,
for ax^2 +bx+c,
product of roots is just c/a
OpenStudy (kanwal32):
ok
OpenStudy (kanwal32):
yes i have heard
OpenStudy (kanwal32):
5/4
OpenStudy (kanwal32):
alpha+beta=-b/a
alpha+beta=c/a
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hartnn (hartnn):
thats correct!
so, AM = sum/2 = 3/4
hartnn (hartnn):
know what HM is ?
OpenStudy (kanwal32):
sqrtab
hartnn (hartnn):
no, thats geometric mean :)
OpenStudy (kanwal32):
ohhh sorry
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hartnn (hartnn):
1/HM = 1/a + 1/b
OpenStudy (kanwal32):
yes
hartnn (hartnn):
so HM = ab/ (a+b)
hartnn (hartnn):
ab = product = 5/2
a+b = sum = 3/2
find HM now
OpenStudy (kanwal32):
(a+b/n)^-1
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OpenStudy (kanwal32):
5/3
hartnn (hartnn):
yep,
HM = 5/3
so now you have both roots
3/4 and 5/3
can you make an equation ?
OpenStudy (kanwal32):
yes
OpenStudy (kanwal32):
so sorry i asked such a silly question
hartnn (hartnn):
i wasn't silly. it was a good question :)
and even silly questions are welcome here, there's always something to learn from silly questions too :)
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