Question

Look at the expression below.

2h + y / 9h^2 - y^2 - 4h^2 / 3h + y

a. (3h + y)
b. (3h - y)(3h + y)
c. (3h + y)(3h + y)(3h - y)
d. 3(h + y)(h - y)

help me please :)

Answer 1

it's this right?

\[\Large \frac{2h + y}{9h^2 - y^2} - \frac{4h^2}{3h + y}\]

Answer 2

just want to be sure I interpreted the problem correctly

Answer 3

okay sorry was using the restroom :P

Answer 4

that's ok

Answer 5

yeahs that right.

Answer 6

You factor the first denominator to get

\[\Large \frac{2h + y}{9h^2 - y^2} - \frac{4h^2}{3h + y}\]
\[\Large \frac{2h + y}{(3h - y)(3h + y)} - \frac{4h^2}{3h + y}\]

The factored denominators are (3h - y)(3h + y) and (3h + y)

The unique factors in the denominator are (3h - y) and (3h + y)

So that means the LCD is (3h - y)(3h + y). You just multiply those unique factors you find in the denominator.

Answer 7

I factored 9h^2 - y^2 by using the difference of squares rule

a^2 - b^2 = (a - b)(a + b)

Answer 8

ffs i can't learn this pellet omfg ima die -_-

Answer 9

just take it one step at a time

Answer 10

i am but i can't seem to get it right :(

Answer 11

it's ok, you'll get it eventually

Answer 12

:;/ let me see.

Answer 13

well D is the only that is different, so i do not think its that 1.

Answer 14

am i wrong?

Answer 15

I wrote the answer above lol

Answer 16

you're looking for the LCD right?

Answer 17

yes

Answer 18

i didn't see that xD

Answer 19

that's ok

Answer 20

okay so its B? lol

Answer 21

correct

Answer 22

thanks

Answer 23

you're welcome