Question

What is the least common denominator of the expression below?

g^2 / 9 - g^2 + 14 + g / 24g + 8g^2

a. (3 + g)
b. 7g^2 + 24g + 9
c. 8g(3 - g)
d. 8g(3 + g)(3 - g)

help me please :)

Answer 1

well..."Common" Denominator just means that the denominators
in two (or more) fractions are common, or the same.

Answer 2

is it D?

Answer 3

yeah i think you may be right on this one

Answer 4

i got d

Answer 5

alright

Answer 6

\[\Large \frac{g^2}{9-g^2} + \frac{14+g}{24g + 8g^2}\]


\[\Large \frac{g^2}{3^2-g^2} + \frac{14+g}{24g + 8g^2}\]


\[\Large \frac{g^2}{(3+g)(3-g)} + \frac{14+g}{24g + 8g^2}\]


\[\Large \frac{g^2}{(3+g)(3-g)} + \frac{14+g}{8g(3 + g)}\]



I'll let you finish up

Answer 7

8g :d?

Answer 8

can i get a medal

Answer 9

so A ??? im so confused now xD

Answer 10

you were right the first time

it's best to go with your gut feeling sometimes

Answer 11

look at the factors in the denominators
and focus on the unique factors

Answer 12

true that

Answer 13

but its least common, and 3 + g are very common lol
how is it D?

Answer 14

the unique factors are: (3+g), (3-g), and 8g

multiply them to get 8g(3+g)(3-g)

Answer 15

(3+g) is a factor, but it's not the whole LCD

Answer 16

okay i see :) thanks

Answer 17

you're welcome

Answer 18

ok perve

Answer 19

welcome hey im 16 what do you expect