Question

Why 0.5! doesn't exists ?

Answer 1

@SolomonZelman

Answer 2

There is no such a thing as a factorial of a non-whole (or not positive) number.

Answer 3

it does exist according to some n! definition mmm
but if you define n! as n=1.2.3.....n as n is integer then
it does not exist couse its not of its domain , ill show u
when it does exist :D

Answer 4

What is the condition due to which you can judge that 0.5! must not exist.

Answer 5

Factorial of whole numbers exists,

\(\large\color{blue}{ \rm 0!=1 }\) RULE
\(\large\color{blue}{ \rm 1!=1 }\)
\(\large\color{blue}{ \rm 2!=1 \times 2=2 }\)
\(\large\color{blue}{ \rm 3!=1 \times 2 \times 3=6 }\)
\(\large\color{blue}{ \rm 4!=1 \times 2 \times 3 \times 4=24 }\)

AND SO ON.....

Answer 6

Well, I really want to say, that just that it is applied when you are choosing something out of something else,

nPr or nCr, you are choosing in wholes, not in 1.2 piece of candy from the bag, or anything like that.....

Answer 7

well by candy it is nCr, but imagine you are taking different combinations for computer password ─ (nPr )

Half of a password (?!!!)

Answer 8

What is the theoritical point ?

Answer 9

I think I posted it above, in blue.

Answer 10

or you want to see what you would see in a math textbook?
I just like explaining things in simpler terms, this is what OS is for.

Answer 11

it's the way long thing we know by practice. I want the original thing or original theory working behind this.

Answer 12

working behind factorial? OR like you want to know about combinations and permutations?

Answer 13

if 0! is one then what will be the 0.5! ??

Answer 14

or 0.998!

Answer 15

factorial of a decimal doesn't exist, unless you approximate it to a whole number and then do the factorial.