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Mathematics 16 Online
OpenStudy (anonymous):

How do i calculate the second derivative of...?

OpenStudy (anonymous):

\[\left( x+1 \right)^{2}e ^{f(x)}\]

OpenStudy (goformit100):

put the given function equals to y

OpenStudy (goformit100):

take log on both sides.

OpenStudy (goformit100):

now do the further process

OpenStudy (anonymous):

Y'=\[2(x+1)e ^{f(x)}+(x+1)^{2}f'(x)e ^{f(x)}\]

OpenStudy (anonymous):

y''=\[2e ^{f(x)}+2(x+1)f'(x)e ^{f(x)}+\]

OpenStudy (anonymous):

How do I do the derivative of the last member of derivative one?

OpenStudy (goformit100):

@SolomonZelman Professor Please help us

geerky42 (geerky42):

Say you have \(g(x) = h(x)~j(x)~k(x)\) So for product rule of three functions or more: \(g'(x) = h'(x)~j(x)~k(x)+h(x)~j'(x)~k(x)+h(x)~j(x)~k'(x)\)

OpenStudy (solomonzelman):

greeky is here, idk how to do this question, not that good at math -:(

OpenStudy (goformit100):

it's ok Professor of Mathematics. No worries.

OpenStudy (solomonzelman):

"proffesor" is anyone who answers easy question to get 3000 badges? hehe openstudy. I wish I learned this, then I would have been helpful, but only this comming year I will be able to do those.

geerky42 (geerky42):

So for last member, you have \( \dfrac{d}{dx}\left((x+1)^2f'(x)e^{f(x)}\right)\\ =\dfrac{d}{dx}\left[ (x+1)^2\right]f'(x)e^{f(x)}\\~~~~~~+(x+1)^2\dfrac{d}{dx}\left[f'(x)\right]e^{f(x)}\\~~~~~~+(x+1)^2f'(x)\dfrac{d}{dx}\left[e^{f(x)}\right]\) Sorry for so messy looks but hope this helps

OpenStudy (anonymous):

Thank you ^^

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