Question

Find the limit of the function algebraically.
lim(x->-3) x^2-9/x^3+3

Answer 1

-18/-24

Answer 2

is it really
\[\frac{x^2-9}{x^3+3}\]?

Answer 3

Yes

Answer 4

if so the limit is just zero
the numerator is zero and the denominator is not

Answer 5

\[\frac{(-3)^2-9}{(-3)^2+3}=\frac{0}{-24}\]

Answer 6

omg my calculator keeps giving me -18

Answer 7

otherwise known as \(0\)

Answer 8

that is because your calculator cannot read your mind

Answer 9

if you type
\[-3^2\] in your calculator you will get \(-9\)

Answer 10

okay my bad

Answer 11

but it should be \((-3)^2=9\)