can someone help??? How many integer solutions has the inequality:x/x+4<=1/x+1
\(\huge\color{blue}{ \frac{x}{x+4} ≤ \frac{1}{x+1}}\)
cross multiply ••••• \(\Large\color{blue}{ x(x+1) ≤ 1(x+4)}\) \(\Large\color{blue}{ x^2+x ≤ x+4}\) \(\Large\color{blue}{ x^2 ~≤ ~ 4}\) \(\Large\color{blue}{ x^2-4 ~~≤ 0}\) \(\Large\color{blue}{ (x-2)(x+2)≤ 0}\)
can you finish the problem off?
i found 2 solutions -2 and 2 ..but i don't know how to find the other 3
i got till that point as well..
yes, so now we are getting x ≤ 2 and x≤ -2
how many integers are there that are less than -2 ?
-3,-4,-5 and so on XD
You should have \(-2\le x\le2\) as a solution set, not \(x\le-2\). The zero product property doesn't work for inequalities.
didn't know that zero product prop. doesn't work for.....
Also, note that \(x=-1\) and \(x=-4\) give undefined expressions, so know to avoid those.
@SolomonZelman, polynomial inequalities can be tricky. What I do is try to picture it (in this case, a parabola shifted down by 4), and see which interval(s) satisfy the inequality. For \(x^2-4\), the parabola dips below the x-axis between -2 and 2.
so then the answers would be -2,-1,0,1 and 2
but how do i know if x is<= to some value or x=>.. ?
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