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Mathematics 12 Online
OpenStudy (anonymous):

Part 1: Write the general form of the equation which matches the graph below. (3 points) Part 2: In complete sentences, explain the process taken to find this equation. (3 points) http://assets.openstudy.com/updates/attachments/51faa5f3e4b0259e2c33a6c5-magbak-1375381008302-10_04g_29.gif

OpenStudy (amoodarya):

vertex is (0,+3) directx is x=-4 f is on (4,3) \[y^2=4px\\(y-y _{0})^2=4p(x-x _{0})\\p=4\\vertex\\is \\(0,+3)\\so\\(y-3)^2=4*4(x-0)\]

OpenStudy (anonymous):

thank you !!!

OpenStudy (tkhunny):

Not to mention the DEFINITION - After finding the Focus. Distance to Focus: \(\sqrt{(x-4)^{2} + (y-3)^{2}}\) Distance to Directrix: \(x+4\) Then a little algebra \(\sqrt{(x-4)^{2} + (y-3)^{2}} = x+4\) \((x-4)^{2} + (y-3)^{2} = (x+4)^{2}\) \(x^{2} - 8x + 16 + (y-3)^{2} = x^{2} + 8x + 16\) \((y-3)^{2} = 16x\) \((y-3)^{2} = 4\cdot4\cdot x\) Always keep your mind open to different approaches. Don't forget the ones you already know!

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