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OpenStudy (anonymous):
OpenStudy (anonymous):
Is this slope?
OpenStudy (anonymous):
I think so
OpenStudy (anonymous):
Okay give me a second.
OpenStudy (anonymous):
\[
4y-x\geq 2x-4y+x\]Add \(x\) to both sides:\[
4y\geq 3x-4y+6
\]Add \(4y\) to both sides\[
8y\geq 3x+6
\]Divide by \(8\) \[
y\geq \frac{3}{8}x+\frac{6}{8}
\]
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OpenStudy (amoodarya):
\[4y-x \ge 2x-4y+6 \\4y+4y \ge x+2x +6\\8y \ge 3x +6 \\now\\first\\graph \\ the \\ line \\8y-3x-6=0\\then\\put (0,0) \\in\]
and check
if work select the area contain (0,0)
if not select other area
OpenStudy (anonymous):
This tells you a few things:
\(y\geq\) means it is shaded above the line.
\(+\frac 68\) tells you that the \(y\) intercept is positive.
OpenStudy (anonymous):
^^ I was too slow D:
OpenStudy (anonymous):
B.
OpenStudy (anonymous):
@nickmifsud1223 @wio @amoodarya @robtobey thank you all so much. Can you please help me with another question?
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OpenStudy (amoodarya):
just do like that !
OpenStudy (anonymous):
Try and do the work from what they instructed on. Wio and Amoodarya gave good instructions.
OpenStudy (anonymous):
@amoodarya I did, and I got (A) for an answer, is that correct answer?