Which graph shows the solution? ..
Is this slope?
I think so
Okay give me a second.
\[ 4y-x\geq 2x-4y+x\]Add \(x\) to both sides:\[ 4y\geq 3x-4y+6 \]Add \(4y\) to both sides\[ 8y\geq 3x+6 \]Divide by \(8\) \[ y\geq \frac{3}{8}x+\frac{6}{8} \]
\[4y-x \ge 2x-4y+6 \\4y+4y \ge x+2x +6\\8y \ge 3x +6 \\now\\first\\graph \\ the \\ line \\8y-3x-6=0\\then\\put (0,0) \\in\] and check if work select the area contain (0,0) if not select other area
This tells you a few things: \(y\geq\) means it is shaded above the line. \(+\frac 68\) tells you that the \(y\) intercept is positive.
^^ I was too slow D:
B.
@nickmifsud1223 @wio @amoodarya @robtobey thank you all so much. Can you please help me with another question?
just do like that !
Try and do the work from what they instructed on. Wio and Amoodarya gave good instructions.
@amoodarya I did, and I got (A) for an answer, is that correct answer?
yes
C. x > 1/2 (-15 + 5 y)
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