How do I simplify this? Incoming..

Question

anonymous · Answer

$$8\sqrt{y^2 -x^2}+8x*\frac{ 1 }{ 2 } (y^2-x^2)^{\frac{ -1 }{ 2 }} *-2x +8x$$

aric200 · Answer

Psssssh

phi · Answer

It does not look promising...

jdoe0001 · Answer

$\bf \large { 8\sqrt{y^2 -x^2}+8x\cdot \frac{ 1 }{ 2 } (y^2-x^2)^{\frac{ -1 }{ 2 }} \cdot -2x +8x
\ \quad \
8(y^2 -x^2)^{\frac{ 1 }{ 2 }}+8x\cdot \frac{ 1 }{ 2 } (y^2-x^2)^{\frac{ -1 }{ 2 }} \cdot -2x +8x
\ \quad \
{\color{brown}{ 8(y^2 -x^2)^{\frac{ 1 }{ 2 }}}}\left[1+x\frac{1}{2}(y^2 -x^2)^1\right]+6x }$

as phi  suggested

jdoe0001 · Answer

hmm sorta got a * MIA

anonymous · Answer

man this thing is wiggedy wiggedy wack

jdoe0001 · Answer

$\bf \large {
8\sqrt{y^2 -x^2}+8x\cdot \frac{ 1 }{ 2 } (y^2-x^2)^{\frac{ -1 }{ 2 }} \cdot -2x +8x
\ \quad \
8(y^2 -x^2)^{\frac{ 1 }{ 2 }}+8x\cdot \frac{ 1 }{ 2 } (y^2-x^2)^{\frac{ -1 }{ 2 }} \cdot -2x +8x
\ \quad \
{\color{brown}{ 8(y^2 -x^2)^{\frac{ 1 }{ 2 }}}}\left[1-2x\frac{1}{2}(y^2 -x^2)^1\right]+8x
}
$

more like

anonymous · Answer

alright now its time for me to set this to 0 and solve for x given y = whatever you want it to equal

anonymous · Answer

man what a pain