Question

The curve on the picture can be a graphic of a function,
how do i know what the function is?

Answer 1

Do you have an image of the picture? Oh! There it is!

Answer 2

yea :D

Answer 3

This is an expression of the type\[\frac{ x+something }{ x-something }\]The only way I knew that is because I am familiar with them.

Answer 4

umm so what that "something" is?

Answer 5

This is a rational function of the form

\[\Large y = \frac{1}{x-h}+k\]

where (h,k) is the center point (where the asymptotes intersect)

Answer 6

okay

Answer 7

but i need the exact one for it

Answer 8

well there are no numbers on that graph

Answer 9

so I don't know where those asymptotes cross

Answer 10

i have these as solutions: y=1+2/x+1,y=1-1/x-1,y=-1+1/x-1,y=-1-2/x+1 and y=1-2/2(x+1)

Answer 11

well again, the graph is missing numbers on the axis to tell me where they cross

Answer 12

so I could easily make up any function

Answer 13

the last one is y=1-1/2(x+1)

Answer 14

they could be -1 and 1

Answer 15

they are the same distance from 0

Answer 16

but those sound like guesses, they could be -5 and 5

Answer 17

well yea..but how do i do it then? :/

Answer 18

well if (h,k) = (-1,1), then

\[\Large y = \frac{1}{x-h}+k\]

\[\Large y = \frac{1}{x-(-1)}+1\]

\[\Large y = \frac{1}{x+1}+1\]

Answer 19

but we don't have that in the solutions :XD

Answer 20

the correct one should be y=1-1/2(x+1)
i just don't know why :|

Answer 21

hmm that seems linear

unless you meant to say

\[\Large y = 1-\frac{1}{2(x+1)}\]

??

Answer 22

that's what i wrote :D

Answer 23

well that 2 is throwing me off and I have no idea how they got that

Answer 24

but I can see how they got those '1's

Answer 25

the negative is there because they flipped everything over the horizontal asymptote

Answer 26

hmm i guess i'll need to ask my teacher that..they do have plenty of ones like this one..

Answer 27

Salazar: without markings on the axes of the graph you've presented, it is not possible to come up with a specific function, but only a general one of the form that Jim Thompson has presented. Please go back and check to ensure that you have copied all of the info from the original problem.

If you'd look carefully at Jim's proposed function, you may recognize that this function is based upon the graph / function y = 1 / x (which you may want to graph for reference purposes). compare the graph of y = 1 / x to that given you in this problem and ask yourself what transformations (i e moving the graph to the right or to the left and/or moving the graph up or down were done to obtain the graph you have presented here.

Subject: 'linear transformations'

Answer 28

it's all correct i did checked it..it's more of a logical problem so that's why they didn't put any markings

Answer 29

but someone did explain it to me an basically all i have to do is find the most similar solutions to it and then throw off all the other ones :D

Answer 30

Do you recognize that the graph presented has both vertical and horizontal asymptotes?

Please duplicate the given graph in the Draw utility, below, and then mark the x- and y- axes. Then YOU decide the x-and y-values for the vertical and horiz asymptotes and mark those also. Then we'll start the business of determining the equation for this function.

Answer 31

My interest is far more in seeingyou come to understand the principles involved here, so that in the future you will be able to solve similar problems yourself with confidence.

Answer 32

oh i solved this! :D

Answer 33

a teacher of mine helped me understand how to do it :)

Answer 34

Glad you have this solved also! Thanks for the medal (for the other problem).

Answer 35

yw :)
i have a log issue now XD
can you check that one out? :D