Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (camerondoherty):

Just Part C

OpenStudy (camerondoherty):

Belinda wants to invest $1000. The table below shows the value of her investment under two different options for two different years: Number of years 1 2 3 Option 1 (amount in dollars) 1100 1210 1331 Option 2 (amount in dollars) 1100 1200 1300 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points) Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points) Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option. (4 points)

OpenStudy (campbell_st):

option 2 is linear.. it just adds $100 per year Option 1 is exponential. it adds 10% each year Option 1 f(n) = 1000(1 + 10/100)^n option 2 f(n) = 100n + 1000 hope it helps

OpenStudy (camerondoherty):

It does thank you!

OpenStudy (camerondoherty):

can u help me with part c though?

OpenStudy (campbell_st):

well for par c just use the equations from part b and let n = 20 to see which is worth more.

OpenStudy (camerondoherty):

its no right?

OpenStudy (camerondoherty):

@geerky42 plz help with part c...

geerky42 (geerky42):

did you try to plug in n = 20 and see if there is any difference?

OpenStudy (camerondoherty):

f(20)=110(20)+1000 f(20)=1000(1+100/100)^20 do i solve these?

geerky42 (geerky42):

yeah

OpenStudy (camerondoherty):

then what?

geerky42 (geerky42):

actually, second one is supposed to be f(20)=1000(1+10/100)^20

geerky42 (geerky42):

well, did you solve these? do you see the big difference?

OpenStudy (camerondoherty):

equation 1 is 3200

OpenStudy (camerondoherty):

and ill redo the second one

geerky42 (geerky42):

sorry, I checked too fast. first one is supposed to be 100(20)+1000

geerky42 (geerky42):

so what did you get for first and second equation?

OpenStudy (camerondoherty):

wait what are the two equations again i just got confused... are they \[f(20)=110(20)+1000\] for the first one and for the second one\[f(20)=1000(\frac{ 1+10 }{ 100 })^{20}\]

geerky42 (geerky42):

First: \[\Large f(20) = 100(20)+1000\] Second: \[\Large f(20) = 1000\left(1+\dfrac{10}{100}\right)^{20}\]

OpenStudy (camerondoherty):

ok ok thank you give me a sec to solve (im a bit slow... xD)

OpenStudy (camerondoherty):

first one: 3000 Second one: \[\frac{ 672749994932560009201 }{ 100000000000000000 }\]

OpenStudy (camerondoherty):

long number -_-

geerky42 (geerky42):

that's right. for second one, you can convert it to decimal; 6727.499949...

OpenStudy (camerondoherty):

and the second one is a lot longer and a hge difference there

OpenStudy (camerondoherty):

and ok

OpenStudy (camerondoherty):

its more than double

geerky42 (geerky42):

So what did you notice about the difference between first one and second one?

OpenStudy (camerondoherty):

its a bigger number, and shell get a much bigger nvestment number using option 2

geerky42 (geerky42):

right. that's something you can write down for part C. :)

OpenStudy (camerondoherty):

oh ok thank you so much u saved meee

geerky42 (geerky42):

You're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!