Factor completely 16a3b7 + 2a6b4 - 22a4b5.

2(8a3b7 + a6b4 - 11a4b5)

2a3b4(8b3 + a3 - 11ab)

a3b4(16b3 + 2a3 - 22ab)

8b3 + a3 - 11ab

Question

Factor completely 16a3b7 + 2a6b4 - 22a4b5.

2(8a3b7 + a6b4 - 11a4b5)

2a3b4(8b3 + a3 - 11ab)

a3b4(16b3 + 2a3 - 22ab)

8b3 + a3 - 11ab

solomonzelman · Answer

I don't play like this.... everyone keeps editing questions in the middle of my replies -:(

solomonzelman · Answer

What do you think is the greatest Common factor ?

anonymous · Answer

if i was you, i would recommend just focusing on the a's and the b's so for now, just look at the (16a^3+2a-22a^4) what can you take out of that?

anonymous · Answer

though im finding it somewhat difficult to see what is the exponent and what is the base

anonymous · Answer

is this your original equation? $$16a3b^7+2a6b^4-22a4b^5$$

jenniferjuice · Answer

attachment

anonymous · Answer

alright that makes this a lot easier thank you

jenniferjuice · Answer

np :)

anonymous · Answer

if you look just at the beginning numbers then (16 + 2 - 22) what can be taken out to simplify that?

jenniferjuice · Answer

-22?

anonymous · Answer

no, what is the common difference here?

jenniferjuice · Answer

18-22?

anonymous · Answer

try not to solve it look at it as if it was like (16x^2+2x-22) what would you take out?

jenniferjuice · Answer

16x^2 ?

anonymous · Answer

no, try just 2.

anonymous · Answer

so now you should have $$2(8a^3b^7+a^6b^4-11a^4b^5)$$

anonymous · Answer

now, lets focus on just the a's (a^3 + a^6 + a^4) try to see what you can take from that?

jenniferjuice · Answer

a6b4?

anonymous · Answer

sorry, in this case that wouldnt be right. the b^4 you got correct, but now the a part.

anonymous · Answer

i would recommend looking at it like 
a*a*a
a*a*a*a*a*a
a*a*a*a.

how many of the a's line up?

jenniferjuice · Answer

13

anonymous · Answer

no, how many line up in horizontal rows, the correct answer here is 3. do you see that?

anonymous · Answer

*vertical* my bad sorry im kinda tired XD

anonymous · Answer

a * a * a
a * a * a (*a*a*a)
a * a * a (*a)

see that?

jenniferjuice · Answer

yes

anonymous · Answer

alright so because they all share at most 3 a's in common you can take out 3 a's or (a^3) so you know you can take out 2a^3 and you already got the b^4 right before so now you've taken out 2a^3b^4. this will leave you with what remaining in the parentheses?

anonymous · Answer

$$2a^3b^4(?)$$

anonymous · Answer

hint: its one of your options

jenniferjuice · Answer

b?

anonymous · Answer

yep perfect.