Question

What are the vertices of the hyperbola given by the equation open parentheses x minus 3 close parentheses squared over 4 end fraction minus open parentheses y plus 7 close parentheses squared over 1 = 1?

Answer 1

@AccessDenied

Answer 2

@abb0t @zepdrix

Answer 3

ur vertices is 3 and -7

Answer 4

the standar form of a hyperbola is (x-h)/a^2 - (y-k)/b^2 = 1....

the coordinates of ur vertices is h and k...

Answer 5

im sorry what?

Answer 6

\[\frac{ (x-h)^2 }{ a^2 }-\frac{ (y-k)^2 }{ b^2 } = 1\]

it is the standard form of hyperbola that opens right and left....
so when u substitute ur equation in thgis form it becomes

\[\frac{ (x-(-3)^2 }{ 4^2 } - \frac{ (y-(7))^2 }{ 1^2} = 1\]

so ur h becomes +3 and ur k becomes -7... got it.?