Two dice are thrown simultaneously. Given that sum of the numbers is NOT more than 5, what is the probability that sum is more than 3?
A.7/10
B.3/10
C.5/6
D.3/4
E.9/10

Question

Two dice are thrown simultaneously. Given that sum of the numbers is NOT more than 5, what is the probability that sum is more than 3? 
A.7/10
B.3/10
C.5/6
D.3/4
E.9/10

anonymous · Answer

@ganeshie8

dan815 · Answer

oops didnt read the full question xD

ganeshie8 · Answer

haha its conditional probability

dan815 · Answer

ya didnt even read that "Not more than 5 part" lol

ganeshie8 · Answer

$$P(A |  B) = \dfrac{P(A \cap B)}{P(B)}$$

anonymous · Answer

I have absolutely no idea how to work that even with the formula. @ganeshie8

dan815 · Answer

doo the prob of more than 3 / prob of not more than 5

dan815 · Answer

its easiest to just draw the table out i guess

ganeshie8 · Answer

I bet below formula will confuse kassie :) $$P(\text{"sum >3" | "sum <= 5" } ) = \dfrac{P(\text{"sum >3"} \cap \text{"sum <= 5"} )}{P(\text{"sum <=5"} )}$$

ganeshie8 · Answer

yeah, better to work it using a table..

dan815 · Answer

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