Question

x^2+9/x^2-4x-45

Answer 1

can u write the equation to be clear...?

Answer 2

is it \[\frac{ x^2 + 9 }{ x^2 - 4x - 45 }\]..?

Answer 3

oh man some simplification and it should find the hole! :O 1

Answer 4

▬ ▬ Sir/Ma'am, A Warm Welcome To Open Study ▬ ▬

Answer 5

I think it must be \(\huge \frac{ x^2 - 9 }{ x^2 - 4x - 45 }\)

\(\huge \frac{ x^2 - 9 }{ x^2 - 4x - 45 }=\frac{(x+9)(x-9)}{x^2-9x+5x-45}\\\huge=\frac{(x+9)(x-9)}{x(x-9)+5(x-9)}=\frac{(x+9)(x-9)}{(x-9)(x+5)}=\frac{x+9}{x+5}\)