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Chemistry 8 Online
OpenStudy (abhisar):

The uncertainity in the position of an electron moving with a velocity of 3*10\(^4\) cm/sec and having an uncertainity of 0.011% in the velocity will be ? Mass of electron = 9.1*10\(^{-28}\) gm

OpenStudy (abhisar):

@chmvijay

OpenStudy (abhisar):

@Somy

OpenStudy (somy):

wait velocity is given

OpenStudy (abhisar):

yep

OpenStudy (somy):

and u want to find?

OpenStudy (abhisar):

we have to find uncertainity in the position

OpenStudy (somy):

right i'd first suggest finding uncertainty of velocity itself since % is given

OpenStudy (abhisar):

okay..so it will be 3.3

OpenStudy (somy):

3*104 cm/sec - 100% X- 0.011%

OpenStudy (somy):

yup

OpenStudy (abhisar):

ohkay i got it !

OpenStudy (abhisar):

Thankyou very much ♥

OpenStudy (somy):

lol u r welcome :*

OpenStudy (somy):

but what is the formula that u use to find position (im curious since idk)

OpenStudy (abhisar):

\(\delta\)X * \(\delta\)V = \(\huge \frac{h}{4\pi m}\)

OpenStudy (somy):

i see :)

OpenStudy (abhisar):

\(\huge\color{green}{ت}\)

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