if v1=(2 -5) and v2=(4 -3), then the angle between the 2 vectors is______degrees. Round your answer to two decimal points
assuming you missed the commas; just work the definition of a dotproduct to solve for alpha:\[|\vec u||\vec v|~\cos\alpha=\vec u \cdot \vec v\]
not sure if definition is proper usage .. maybe identity?
I am still confused..
youll have to be more descriptive of your confusion ... my mind reading skills are subpar.
lol!
How do I find the angle based on the two points?
by working the setup that the dot product gives us.
do the dot; divide by the lengths, and inverse the cosine
have you learned dot product (aka inner product)?
I think, dont you just multiply both of the xs, and ys, and add them together
yes
yes, thats the dot process
lengths and inverse cosine are all thats left to determine
think of length is the sqrt of a vector dotted to itself ...
23 is the dot product!
(2 -5) (4 -3) ------ 8+15 = 23 correct
Now what do I do, you said divide by length????
the lengths are therefore just (2 -5) (2 -5) ------ 4+25, sqrt(29) (4 -3) (4 -3) ----- 16+9, sqrt(25)
yes, lets work some algebra :) \[|\vec u||\vec v|~\cos\alpha=\vec u \cdot \vec v\] \[\cos\alpha=\frac{\vec u \cdot \vec v}{|\vec u||\vec v|}\] \[\alpha=\cos^{-1}\left(\frac{\vec u \cdot \vec v}{|\vec u||\vec v|}\right)\]
\[\alpha=\cos^{-1}\left(\frac{23}{5\sqrt{29}}\right)\]
so the angle is the answer of that!!
keep in mind that the inverse is a radian measure and to convert to degrees may need a 180/pi factor
yes
so i do cos^-1(24.77)
depends on how accurate you need to be, but yes
I got domain error on my calculator
your division was wrong :) 23/(5sqrt(29)) is 0.85419...
oh thank you so much, :))))))) You were so helpful!! the answer is 31.33!!!!
the domain of the inverse cosine function is -1 to 1 .... hence 24 is not in the domain
31.33 degrees is correct
good luck :)
Thank You!
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