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Mathematics 4 Online
OpenStudy (amtran_bus):

URGENT CALC HELP!

OpenStudy (amtran_bus):

Find a parabola with equation y = ax2 + bx + c that has slope 2 at x = 1, slope −10 at x = −1, and passes through the point (2, 13).

OpenStudy (amtran_bus):

I need someone to guide me, I do not know where to start..

OpenStudy (amtran_bus):

Derivative is 2ax+b

OpenStudy (anonymous):

I'll get to you as soon as I see what's so hard about all this >:)

OpenStudy (anonymous):

LOL kidding Derivative is slope, and the slope is 2 when x = 1. substitute ^.^

OpenStudy (anonymous):

I don't think this is Calculus..

OpenStudy (amtran_bus):

Well, haha its not hard maybe but just I'm running about of time :)

OpenStudy (anonymous):

Seems like simple Algebra I.

OpenStudy (anonymous):

Then quickly now. Derivative (slope) is 2 when x = 1. Sub them

OpenStudy (amtran_bus):

Into what I gave?

OpenStudy (anonymous):

the derivative 2ax + b, yes.

OpenStudy (anonymous):

Okay, since you're in a hurry, and the fact that you're a sentient bus, I'll demo the first equation, but you have to do the second. When x = 1, the slope 2ax + b is 2. This all means that when x = 1 (sub x into the derivative) ... 2a + b the slope is 2. Then the derivative is equal to 2... 2a + b = 2 Understand?

OpenStudy (amtran_bus):

Thanks, I think so!

OpenStudy (anonymous):

Okay... set up the second equation... when x = -1, the slope is -10 What equation do we get from that?

OpenStudy (amtran_bus):

-10

OpenStudy (anonymous):

...and I'm sure there's a star somewhere in the night sky where -10 is an equation, but not here :D Come on, just do what I did with the first equation ^.^ looking back... I don't think -10 is an equation anywhere :P

OpenStudy (amistre64):

-10 is an equation of a line :) y = -10

OpenStudy (anonymous):

:( ok

OpenStudy (amistre64):

-10 by itself is not equation, since there is no = sign in it .... but then mathmatikers get lazy a lot of the time.

OpenStudy (amistre64):

you have a system of equation to determine:\[2ax_1+b=y_1\\2ax_2+b=y_2\] solve for a,b then use them to determine:\[ax_3^2+bx_3+c=y_3\]

OpenStudy (anonymous):

I lost him :( Why do people keep running away from me....

OpenStudy (amistre64):

its the green tights .. makes them uncomfortable, but thats just a guess :)

OpenStudy (anonymous):

:( Oh well... on to the next :D

OpenStudy (anonymous):

oh wait.... talking bus is back :D

OpenStudy (amtran_bus):

Hum. So it is 3x^2-4x+9!!!!!!!\ ?????

OpenStudy (amistre64):

we could just as well setup a 3 system of equation 2ax1 +b +0c=y1 2ax2 +b +0c=y2 a(x3)^2+bx3+c =y3 \[rref: \begin{pmatrix} 2x_1&1&0&|&y_1\\ 2x_2&1&0&|&y_2\\ x_3^2&x_3&1&|&y_3\\ \end{pmatrix}\]

OpenStudy (anonymous):

Not that I don't like magic... but, maybe your particular brand of magic could use a little more explanation :)

OpenStudy (amistre64):

1,2 -1,10 2,13 rref{{2,1,0,2},{-2,1,0,-10},{4,2,1,13}} http://www.wolframalpha.com/input/?i=rref%7B%7B2%2C1%2C0%2C2%7D%2C%7B-2%2C1%2C0%2C-10%7D%2C%7B4%2C2%2C1%2C13%7D%7D yes, 3,-4,9

OpenStudy (amistre64):

its an augmented matrix solution to the 3equations in 3unknown

OpenStudy (amistre64):

linear algebra :)

OpenStudy (anonymous):

I'll stick to faerie dust. Well done anyways XD

OpenStudy (amistre64):

... my cats ate all my dust

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