Question

find the sum of the geometric series with a1=7, r=2, and n=14

Answer 1

7(2^14 -1)/2^14 -1. The answer is 7.

Answer 2

thanks

Answer 3

can u help me on these one find a1 for the geometric series with r=3 and S6=364

Answer 4

your a is 364

Answer 5

ok thanks

Answer 6

just put the values given to you in the formula of sum of geometric progression

Answer 7

ok

Answer 8

sn = a1 (1 - r^n) / (1 - r)
a1 = 7
r = 2
n = 14
now we sub
s14 = 7 (1 - 2^14) / (1 - 2)
s14 = 7 (1 - 16384) / -1
s14 = 7 (- 16383) / -1
s14 = -114681/-1
s14 = 114681

sum of all 14 terms is 114681

Answer 9

i did that but it was wrong

Answer 10

did you get the same answer ? Is the problem written correctly ? Did they want the sum or just the 14th term ?

Answer 11

oh but i think i put 114681/2 i made a mistake i subtracted wrong

Answer 12

they wanted the sum

Answer 13

it is just 114681

Answer 14

ok

Answer 15

can u help me on these on Find r for the geometric series S5=484, a1=4, and a5=324