Ooookay...I was going to try the next one by myself but they hit me with a fraction ;-;

Find the domain:
$$g(x)\frac{ 1 }{ x^{2}+1}-\frac{ 1 }{ x^{2}-1 }$$

Question

Ooookay...I was going to try the next one by myself but they hit me with a fraction ;-;

Find the domain:
$$g(x)\frac{ 1 }{ x^{2}+1}-\frac{ 1 }{ x^{2}-1 }$$

anonymous · Answer

Okay, we know that in a fraction the denominator cannot be zero, right?

anonymous · Answer

Yes.

anonymous · Answer

So, what values of x make the denominator in either fraction zero?

anonymous · Answer

I think it's 1 and -1 except...there's x^2...still there so i don't think that's right

anonymous · Answer

That is correct. In the second fraction, both 1 and -1 would set the denominator equal to zero. Thus, the domain is "All real numbers except 1 and -1"

anonymous · Answer

Arigatou gozaimasu!

anonymous · Answer

Um. You're welcome.