Question

Ooookay...I was going to try the next one by myself but they hit me with a fraction ;-;

Find the domain:
\[g(x)\frac{ 1 }{ x^{2}+1}-\frac{ 1 }{ x^{2}-1 }\]

Answer 1

Okay, we know that in a fraction the denominator cannot be zero, right?

Answer 2

Yes.

Answer 3

So, what values of x make the denominator in either fraction zero?

Answer 4

I think it's 1 and -1 except...there's x^2...still there so i don't think that's right

Answer 5

That is correct. In the second fraction, both 1 and -1 would set the denominator equal to zero. Thus, the domain is "All real numbers except 1 and -1"

Answer 6

Arigatou gozaimasu!

Answer 7

Um. You're welcome.