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Mathematics 13 Online
OpenStudy (anonymous):

I need help! :| What kind of relationship does this table describe? Figure in comments! Thx. :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 Remember me? Help me out? ;)

jimthompson5910 (jim_thompson5910):

Are you given a list of choices? This question seems a bit vague.

OpenStudy (anonymous):

Yeah, I don't even know why there are statistics questions like this in my Geometry course >.<

jimthompson5910 (jim_thompson5910):

yeah that is strange

OpenStudy (anonymous):

The options are: 1. This table is an example of the principle of independence. 2. This table is not an example of the principle of independence. 3. There is not enough information to answer this question.

jimthompson5910 (jim_thompson5910):

Ok let's set up some notation let A = person has a membership, B = person attends one or more classes

OpenStudy (anonymous):

All of these questions are very vague and even opinionated >.< Seems so silly to me. Look at this one! It asks me if it's fair..

jimthompson5910 (jim_thompson5910):

well hold on, we're still on the last one

jimthompson5910 (jim_thompson5910):

with A = person has a membership, B = person attends one or more classes we can say P(A) means the probability of someone having a membership P(B) the probability a person attends one or more classes

OpenStudy (anonymous):

Yeah, I'm just saying. :p Ok so a = membership b = attends classes

jimthompson5910 (jim_thompson5910):

what is P(A and B) equal to?

OpenStudy (anonymous):

It's equal to...... idk.

jimthompson5910 (jim_thompson5910):

how many people have a membership AND attend one or more classes

OpenStudy (anonymous):

17?

jimthompson5910 (jim_thompson5910):

this is out of 70 people in total, so P(A and B) = 17/70

jimthompson5910 (jim_thompson5910):

now what is P(A) equal to?

OpenStudy (anonymous):

23/70

jimthompson5910 (jim_thompson5910):

A is the event that someone having a membership

jimthompson5910 (jim_thompson5910):

how many people have a membership

OpenStudy (anonymous):

oh. 40/70

jimthompson5910 (jim_thompson5910):

now compute P(B)

OpenStudy (anonymous):

39/70?

jimthompson5910 (jim_thompson5910):

B = person attends one or more classes so look in the bottom row of the column that says "attends one or more classes"

OpenStudy (anonymous):

Oh I'm sorry >.< 31/70

jimthompson5910 (jim_thompson5910):

now if events A and B were independent, then P(A and B) = P(A) * P(B) however, P(A and B) = P(A) * P(B) 17/70 = (40/70)*(31/70) 0.24285714285714 = 0.2530612244898 So the equation is false. This means that events A and B are NOT independent. So they are dependent events.

OpenStudy (anonymous):

Interesting.. That was quite the question o.O Thx for the help :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

Did you look at the other one? it's a ridiculous question >.<

jimthompson5910 (jim_thompson5910):

Yeah I'm looking at it now, and still thinking

jimthompson5910 (jim_thompson5910):

Well here's the dilemma: to be "fair" means everyone gets an equal shot. So does that mean everyone gets the same number of ping pong balls (regardless of how bad/good they play)? Or do you skew it to favor those who struggled and played poorly? If you skew it, how do you skew it? How do you quantitatively alter the playing field to make things more fair. Sadly I'm not sure of these questions. I think some skewing needs to happen but I don't know how much. You definitely don't want to go too far and end up over-favoring the bad teams.

OpenStudy (anonymous):

Yeah, isn't that a weird question? Like how am I suppose to answer that >.<

jimthompson5910 (jim_thompson5910):

agreed, and I'm not really great with sports statistics or anything

OpenStudy (anonymous):

Oh well. Thx for the help though :P I'll figure it out.

jimthompson5910 (jim_thompson5910):

and to make matters worse, idk how they're getting 250, 199, etc etc those numbers seem arbitrary

OpenStudy (anonymous):

exactly. maybe it is just a "trick" question kind of. The answer is just no because it betrays the definition of "fair"... Who knows..

jimthompson5910 (jim_thompson5910):

In terms of pure statistics, the answer could be "no" since not all teams in the draft have the same number of ping pong balls. But idk 100%

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