Question

A package contains 6 candy canes, 2 of which are cracked. If 4 are selected, find the probability of getting no cracked candy canes

Answer 1

what is the total combination of selecting 4 candy canes?

Answer 2

is it 6

Answer 3

no

Answer 4

4C2

Answer 5

The total is 6 candy canes. 2 of them are cracked and 4 of them are no cracked.
Any single selection of these from that package includes the probability 4/6 to be no cracked.
Then it is needed to have 4 no cracked candy canes from the package, namely 4 attempts to select each no cracked. Therefore, according to the Multiplication Rule the requested probability is:
(4/6) *(4/6) *(4/6) *(4/6) = 0.19753 or 19,75%.