A spherical snowball is melting in such a way that its diameter is decreasing at rate of 0.1 cm/min. At what rate is the volume of the snowball decreasing when the diameter is 12 cm

Question

anonymous · Answer

Help I dont know how to do this

anonymous · Answer

you got the formula for the volume of a cone?  is so this will take one minute (less)

anonymous · Answer

lol i meant "volume of a sphere"

anonymous · Answer

4/3 pi (R)^3

anonymous · Answer

ok well that has an $r$ and you want it with $d$ but no matter
if the diameter decreases at a rate of $.1$ then a guess the radius decreases at a rate of $.05$

anonymous · Answer

$$V=\frac{4}{3}r^3$$
$$V'=3r^2r'$$

anonymous · Answer

put in $r=6,r'=.05$ and you are done

anonymous · Answer

I got it ! :) thanks

anonymous · Answer

yw

anonymous · Answer

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anonymous · Answer

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anonymous · Answer

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