A 12 foot ladder is leaning against a wall. If the top slips down the wall at a rate of 2 ft/s, how fast will the foot be moving away from the wall when the top is 11 feet above the ground? The foot will be moving at__________ft/s.
3.33 ft/s
thanks
any time
wait i got it wrong,
what ?
can you give me some more decimals?
look the rational expression is \[\frac{ 20 }{ \sqrt{44} }\]
im still getting it wrong :(
|dw:1404184202354:dw|
but excuse me i plugged h for 10 instead of 11 sorry !!
just a sec
4.5929
im still getting it wrong for some reason, i just cant figure it out
whaaaaa ?? do you know how to solve it ??
like I got the same thing you did
beware of answer with no splanation
look
\[x^2+y^2=12^2\\ 2xx'+2yy'=0\\ x'=-\frac{y}{x}y'\]
plug in the numbers now
im getting 4.5929
by applying the Pythagorean equation we get : \[12^2 = h^2 + w^2\] and when we simplify it to get : \[w=\sqrt{144 - h^2}\] we then differentiate it and plug in the numbers
@satellite73 i did explained the answer, if you look up you will see a picture of the problem we have
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