Question

Solve x2 + 10x = -21

Answer 1

What do you have to solve there? Solve for x?

Answer 2

I would solve using the quadratic formula

Answer 3

Guessing method?

Answer 4

so \[x=((-b)\pm \sqrt{b^2-4ac)})/2a\]

Answer 5

where ax^2 + bx = -c are your a, b, and c values

Answer 6

so for your problem. 1 = a, 10 = b and 21 = c (if you add the 21 to both sides and make it positive)

Answer 7

so plug those numbers into your equation

Answer 8

so plug those numbers into your equation\[x= (-(10) \pm \sqrt{(10)^2-4(1)(21)}/2(1)\]

Answer 9

and solve from there

Answer 10

@Katerrah did you get your two answers?

Answer 11

Can you be clear on what you're trying to solve for, hun?

Answer 12

x^2 + 10x = -21
x^2 + 10x + 21 = 0
x^2 + 3x + 7x + 21 = 0
x(x+3) + 7(x+3) = 0
(x+3)(x+7) = 0
x = -3 or x = -7

Answer 13

@TechnoSoul Use `\dfrac{}{}` next time. it makes fraction more readable

example: `\dfrac{1}{2}` display \(\dfrac{1}{2}\)

Answer 14

x=-7, -3 actually, I don't think there should be an or?