Question

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Answer 1

The complete sollution set of the inequaltity
\[\frac{ 5x-1 }{ x ^{2}+3 }<1\] is

Answer 2

@myininaya

Answer 3

@satellite73 please help me

Answer 4

start with \[\frac{5x-1}{x^2+3}-1\leq 0\]

Answer 5

then subtract
a miracle will occur, you will be able to factor the numerator

Answer 6

will since x^2+3 >0 u can shift it to the other side it will be much easy

Answer 7

I did that took the lcm and everything and moved that x^2 +3 to the R.H.S
But i don't get a perfect answer

Answer 8

well*

Answer 9

good point !!

Answer 10

5x-1-x^2+3 <0

5x+2-x^2 < 0
x^2-5x-2 > 0

Answer 11

like this
\(5x-1 <x ^{2}+3\)

Answer 12

still it is a miracle
you get
\[\frac{(x-4)(x-1)}{x^2+3}\geq 0\]

Answer 13

but @ikram002p has totally better method, much easier with no fractions!!

Answer 14

We can transfer that only when there is a 0 in the R.H.S right?

Answer 15

u have a typo , check -3

Answer 16

@No.name
\(5x-1-x^2-3 <0 \)
-x^2+5x-4 < 0
x^2-5x+4> 0
its Quadratic inequality
just solve it

Answer 17

(x-4)(x-1) > 0

(- infinity to 4 _) U ( 1 to infinity ) ????

Answer 18

yessssss