Question

Logarithms

Answer 1

ln(x+z) + ln(x-2y+z) =2ln(x-z) then,
(a)2y=x+z
(b)y^2=xz
(c)z^2=yz
(d)y=\[\frac{ 2xy }{ x+z }\]

Answer 2

mmm maybe this could work ?
ln(x+z) + ln(x-2y+z) = ln ([x+z] *[x-2y+z]) = ln (x-z) ^2

Answer 3

Probably ,
cancel out those logs

wait doing it

Answer 4

yx+yz-2zx = 0 after that

Answer 5

x^2-2xy+xz+xz-2yz+z^2 = x^2 - 2zx + z^2

Answer 6

-2xy+xz+xz-2yz = - 2zx
-2y(x+z)+2xz=-2xz
-2y(x+z) =-4xz

y(x+z) =2xz

mm getting this again :-\
\(y=\large \frac{2xz}{x+z}\)
sure from the last option ? can u check if you dint made a typo ?

Answer 7

Yes you are right i might have made a arithmatic error thanks a million

Answer 8

ohhh np ;)