What is the distance between points (1, 4) and (9, 16)? Round to the nearest tenth. i got 14
you can use pythagorean theorem the square of the distance = (change in y)^2 + (change in x)^2
sqrtx2-x1+y2-y1 \[\sqrt{(9-1)^{2}+(16-4)^{2}}\] \[\sqrt{64+144} = \sqrt{208}\]
to the nearest tenth means the answer to one decimal place
so is 14.4??
yes
The midpoint between points (–3, 8) and (3, –4) is (0, y). What is y? can you help me
always calculate to one more place and then round example for this problem you got 14.42 to one place 2 is less than 5 so drop it and the answer is 14.4
if the calculated amount was 11.47 then the answer would be 11.5
mid-point (x1 + x2)/2 , (y1 + y2)/2 use the absolute value
how about if you draw it so it's easier to see?
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|dw:1404194734138:dw|
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