Question

What is the electronic configuration of an element in its first excited state which is isoelectronic with O\(_2\)
[Ne]3s\(^2\)3p\(^3\)3\(d^1\)
[Ne]3s\(^2\)3p\(^4\)
[Ne]3s\(^1\)3p\(^3\)3d\(^2\)
[Ne]3s\(^1\)3p\(^5\)

Answer 1

Yes! There is 2 oxygens making up 16electrons and [Ne] 3s^2 3p^4 is Sulfur with 16 electrons as well making both oxygen and Sulfur isoelectronic with each other.

Answer 2

I tried =.=

Answer 3

How is Scandium the answer?

Answer 4

wait lol im still thinking

Answer 5

yeah i guess my first choice is the right one [Ne] 3s2 3p4

Answer 6

but

Answer 7

Excited state

Answer 8

hm wait a sec

Answer 9

its last one

Answer 10

Hmmm..it will be A, i figured it out.

Answer 11

Thnx @Somy @Mateaus !

Answer 12

are u sure its first one?

Answer 13

i did think its first one also

Answer 14

but i doesn't really match

Answer 15

because P orbital has half filled stability

Answer 16

Iso to O\(_2\), so number of electrons will be 16...EC for ground state will be [Ne]3s\(^2\)3p\(^4\)

Answer 17

for O2 its s2 p4
excited state is when an electron moves to a higher energy level
thats why i thought i'd be last one then

Answer 18

Now, in first excited state