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the set of values of a for which \[x^2+ax+\sin^{-1} (x^2-4x+5)+\cos^{-1} (x^2-4x+5)\]has at least one real solution is
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@geerky42 ? @annas ? @beccamarx19 ? @Conqueror ? @Destinymasha ? @elementwielder ? @Future_UsArmy_MP ? @ganeshie8 ?
i think this would be simplified to
i think this would be simplified to \[x^2+ax+\pi/2=0\]
now how to solve further?
should i apply b^2-4ac>=0
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bu the answer is not coming correct if i apply it!!!
@mathmale ?
@naylah ? @blues ?
What you have given is an expression. I cannot seen why an expression has a solution.
Should there be another condition that \[x ^{2}-4x+5\le1 \] ie x=2. Thus a=-8-pi/4
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