Question

A covalent is found to contain 36.8% nitrogen and 63.2% oxygen. What is the empirical formula for this solid?

NO
NO1.5
N2O3
N3O2

Answer 1

@Abhisar how do you do this one?

Answer 2

Note % as mass
Number of Moles=Mass(g)/Molar Mass(g/mol)
36.8/14,63.2/16
Divide by the smallest figure
2.628 moles of Nitrogen,3,95 moles of oxygen
2.628/2.628. 3.95/2.628
1,1.50

Answer 3

NO1.5

Answer 4

but you cannot work with a fraction, you must work with a whole number

Answer 5

multiply by 2 to get N2O3

Answer 6

Ok. I see now thank you berry much!!

Answer 7

your welcome :D