Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−2, y+8) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
@ganeshie8
Yes, apply the given rule for each vertex
given rule : (x−2, y+8)
apply it for A (−2, 2) : A' = (−2-2, 2+8) = (-4, 10)
I have just subtracted 2 from x coordinate and added 8 to the y coordinate
Is that clear ?
I'm still confused. I have know idea what to do here @ganeshie8
try to apply the given rule for the vertex B
B = (−2, 4) subtract 2 from x coordinate, add 8 to y coordinate, wat do u get ?
(-4,12) ? sorry my computer is slow
Excellent !!
so thats the image of B : B' = (-4, 12)
oops @ganeshie8
find the images of C and D also
how do I do that?
same way : C = (2, 4) subtract 2 from x coordinate, add 8 to y coordinate, wat do u get ?
(0, 12)
Yep, thats the image of C : C' = (0, 12)
find the image of D similarly
D = (2, 2) D' = ?
(0, 10)
Correct ! you're done
omg @ganeshie8 thank you so much! but what would I write for my final answer?
so what would you write for the characteristics?
Join our real-time social learning platform and learn together with your friends!