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Mathematics 9 Online
OpenStudy (anonymous):

Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−2, y+8) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

Yes, apply the given rule for each vertex

ganeshie8 (ganeshie8):

given rule : (x−2, y+8)

ganeshie8 (ganeshie8):

apply it for A (−2, 2) : A' = (−2-2, 2+8) = (-4, 10)

ganeshie8 (ganeshie8):

I have just subtracted 2 from x coordinate and added 8 to the y coordinate

ganeshie8 (ganeshie8):

Is that clear ?

OpenStudy (anonymous):

I'm still confused. I have know idea what to do here @ganeshie8

ganeshie8 (ganeshie8):

try to apply the given rule for the vertex B

ganeshie8 (ganeshie8):

B = (−2, 4) subtract 2 from x coordinate, add 8 to y coordinate, wat do u get ?

OpenStudy (anonymous):

(-4,12) ? sorry my computer is slow

ganeshie8 (ganeshie8):

Excellent !!

ganeshie8 (ganeshie8):

so thats the image of B : B' = (-4, 12)

OpenStudy (anonymous):

oops @ganeshie8

ganeshie8 (ganeshie8):

find the images of C and D also

OpenStudy (anonymous):

how do I do that?

ganeshie8 (ganeshie8):

same way : C = (2, 4) subtract 2 from x coordinate, add 8 to y coordinate, wat do u get ?

OpenStudy (anonymous):

(0, 12)

ganeshie8 (ganeshie8):

Yep, thats the image of C : C' = (0, 12)

ganeshie8 (ganeshie8):

find the image of D similarly

ganeshie8 (ganeshie8):

D = (2, 2) D' = ?

OpenStudy (anonymous):

(0, 10)

ganeshie8 (ganeshie8):

Correct ! you're done

OpenStudy (anonymous):

omg @ganeshie8 thank you so much! but what would I write for my final answer?

OpenStudy (anonymous):

so what would you write for the characteristics?

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