x - 7/x2 - 49 Find all numbers for which the rational expression is not defined.
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hi :)
spamming again
@goformit100 dont worry :) ill help her
:)
ight lets take a look at the question :)
okay
ok so all you want is me to solve the equation?
help me out with each step im not getting it
lol ok no prob to help and explain the steps right?
yes thank you :)
ok :)
Final result : x3 - 49x2 + 7 ————————————— x2 Step by step solution : Step 1 : 7 Simplify x + —— x2 Rewriting the whole as an Equivalent Fraction : 1.1 Adding a fraction to a whole Rewrite the whole as a fraction using x2 as the denominator : x x • x2 x = — = —————— 1 x2 Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator Adding fractions that have a common denominator : 1.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: x • x2 + 7 x3 + 7 —————————— = —————— x2 x2 Equation at the end of step 1 : (x3 + 7) ———————— - 49 x2 Step 2 : x3+7 Simplify ———— - 49 x2 Rewriting the whole as an Equivalent Fraction : 2.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using x2 as the denominator : 49 49 • x2 49 = —— = ——————— 1 x2 Trying to factor as a Sum of Cubes : 2.2 Factoring: x3 + 7 Theory : A sum of two perfect cubes, a3 + b3 can be factored into : (a+b) • (a2-ab+b2) Proof : (a+b) • (a2-ab+b2) = a3-a2b+ab2+ba2-b2a+b3 = a3+(a2b-ba2)+(ab2-b2a)+b3= a3+0+0+b3= a3+b3 Check : 7 is not a cube !! Ruling : Binomial can not be factored as the difference of two perfect cubes Polynomial Roots Calculator : 2.3 Find roots (zeroes) of F(x) = x3 + 7 Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient In this case, the Leading Coefficient is 1 and the Trailing Constant is 7. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,7
thank u
may i have medal :)
yes i am going to repost this and just comment on it like ur welcome and ill give you a medal
its cool bbb91 :) you can give it to her :)
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